Materials & Quantities

Isolated Ground Rod Earth Resistance Calculator (Dwight's Formula)

Calculate a single driven ground rod's earth resistance using Dwight's formula.

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How strongly the surrounding soil resists electrical current flow.

Soil resistivity varies widely with moisture content, temperature, and composition. For an actual site, measure it directly (e.g. with a Wenner four-pin test) rather than assuming a textbook value.

The length of the ground rod actually driven into the earth.

A standard driven ground rod is commonly 2.4 m (8 ft) long; longer rods or multiple rods reduce resistance further in high-resistivity soil.

The rod's outer diameter.

Common ground rod diameters are 5/8 in (0.0159 m) and 3/4 in (0.0191 m).

Estimated ground rod resistance

39.9 Ω

Medium confidence

Soil resistivity varies significantly with moisture, temperature, and composition — use a field-measured value (e.g. Wenner four-pin test) for your actual site rather than an assumed value. NEC 250.53(A)(2) requires a single rod to test at 25Ω or less, or a second rod must be added; this calculator estimates the resistance, it does not replace an actual field measurement.

Then change the inputs to see how far the answer moves.

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How this was calculated

Formula source(s)

  • Dwight's formula for a single driven ground rod: R = (ρ ÷ (2×π×L)) × (ln(8L÷d) − 1), where ρ is soil resistivity, L is the rod's driven length, and d is the rod diameter — a well-established, widely-cited formula for estimating single ground rod resistance (IEEE Std 142)

Inputs used

Soil Resistivity ρ (Ω·m)
100
Rod driven length
8 ft
Rod Diameter d (m, e.g. 0.0159 for 5/8 in)
0.02
Final result39.89 Ω

Confidence note: Soil resistivity varies significantly with moisture, temperature, and composition — use a field-measured value (e.g. Wenner four-pin test) for your actual site rather than an assumed value. NEC 250.53(A)(2) requires a single rod to test at 25Ω or less, or a second rod must be added; this calculator estimates the resistance, it does not replace an actual field measurement.

What this calculation does not cover

  • Dwight's formula assumes one uniform soil for the full depth of the rod, and real ground is layered. A wet clay skin over dry sand, or two feet of topsoil over rock, cannot be reduced to a single resistivity — and if the rod refuses on rock at 1.2 m then the length in the formula is 1.2 m, not the 2.4 m of steel that was bought. A Wenner traverse at several pin spacings reveals the profile; one number conceals it, and the error runs to a factor rather than a percentage.
  • Resistivity is seasonal, and the shallow soil moves the most. It climbs steeply as ground dries and again as it freezes, where it can rise by an order of magnitude, so the upper metre — the part that dries and freezes — contributes least at exactly the times it is needed. A rod that measures 20 Ω after spring rain can be well past the 25 Ω threshold in February or in a drought, which is why driving below the frost line does far more than diameter ever will.
  • One isolated rod. Add a second and the resistance does not halve, because the two current fields overlap — set them closer than the driven length apart and the pair behaves more like a single larger electrode than like two in parallel, which is the reason a minimum separation exists at all. Nor does this see the rest of the electrode system: a concrete-encased electrode, a metal water service or bonded building steel sits in parallel with the rod and usually dominates whatever a fall-of-potential or clamp-on test actually reads.
  • A low rod resistance does not clear a fault. On a grounded AC system the fault current returns to the source along the equipment grounding conductor, and the earth is explicitly not permitted to serve as that path — a flawless 5 Ω rod will not operate a breaker. The rod is there for lightning, for static and for holding the system's voltage reference, so ohms in the ground are no substitute for a continuous low-impedance bonded return.

Add the equipment this sizes

This result is a specification — 39.9 Ω — not a quantity. Put the thing it sizes into your project: how many, what you call it, and your supplier’s price.

8 ft
Schematic, drawn to the proportions you entered — not to scale on screen.

Computed in your browser — nothing you enter is uploaded. Presented in US customary units and US trade terminology. Where a formula follows a published standard, that standard and its edition are cited beside it on this page; where none governs, the page says so. Local amendments override model codes — verify against the code in force where you build.

Sources checked 2026-09-06 · in the site-wide review of 2026-09-06 · v1.0.1

Regulatory standards & verification citations1
  1. Dwight's formula for a single driven ground rod: R = (ρ ÷ (2×π×L)) × (ln(8L÷d) − 1), where ρ is soil resistivity, L is the rod's driven length, and d is the rod diameter — a well-established, widely-cited formula for estimating single ground rod resistance (IEEE Std 142)
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Now that you have the number

These guides cover the work this quantity is for — the first ones run this calculator inside the section that raises the question.

Called something else where you work? Earthing and grounding — the term in each market, how close the equivalence really is, and the standard that governs it.

How to calculate isolated ground rod earth resistance (Dwight's formula) in 4 steps

  1. Soil Resistivity ρ (Ω·m)How strongly the surrounding soil resists electrical current flow.
  2. Rod driven lengthThe length of the ground rod actually driven into the earth.
  3. Rod Diameter d (m, e.g. 0.0159 for 5/8 in)The rod's outer diameter.
  4. Estimated ground rod resistanceThe tool computes the estimated ground rod resistance from those figures and shows the formula, its sources, and a confidence rating alongside it.

Estimated ground rod resistance by rod driven length

Page defaults, not your figures above.

Rod driven lengthEstimated ground rod resistance (Ω)
4 ft70.7
6 ft50.7
8 ft39.9
10 ft33.1
12 ft28.4
14 ft24.9

Frequently asked questions

What does Dwight's formula calculate?
It estimates the earth resistance of a single driven ground rod: R = (ρ ÷ (2×π×L)) × (ln(8L÷d) − 1), where ρ is soil resistivity, L is the rod's driven length, and d is the rod's diameter. It's a well-established, widely-cited formula (per IEEE Std 142) for single ground rod resistance.
Why does rod diameter matter so little compared to rod length?
Because diameter only appears inside the logarithm term (ln(8L/d)), while rod length appears both inside the logarithm and as a direct divisor: driving a longer rod lowers resistance far more effectively than using a thicker one. Doubling the diameter has a small effect on the result.
Is this calculated value good enough for a code compliance test?
No — this is an estimate only. Soil resistivity varies significantly with moisture, temperature, and composition, so it should be field-measured (e.g. via a Wenner four-pin test) for your actual site. NEC 250.53(A)(2) requires a single rod to test at 25Ω or less (or a second rod must be added), and that determination must come from an actual field measurement, not a calculated estimate.
Preliminary estimate, not certified engineering. This tool produces an indicative quantity calculation for planning purposes only — it is not a certified structural analysis, a guaranteed material takeoff, or a substitute for building department approval. Always verify measurements on-site and have a licensed contractor or structural engineer review any load-bearing, code-sensitive, or safety-critical work before purchasing materials or starting construction. Spotted an arithmetic or standards error? Report it to contact@craftquantities.com with your inputs — a confirmed fix gets a permanent check of its own, so the same mistake cannot come back.