SettingsSettings for this calculationUS
The total length of the boundary the fence will follow.
Measure the full loop the signal wire needs to run, including any exclusion zones (like a driveway) built into the layout.
The one-way distance from the transmitter (usually in a garage) to where the boundary loop starts.
This section uses twisted wire, which carries no signal and can be routed to cross itself without affecting the fence, unlike the boundary loop.
Boundary wire needed
2 x 500 ft rolls
- Total wire needed (with waste)
- 646.8 linear ft
They open the calculator with your figures already in it
In-Ground Dog Fence Wire Calculator: 2 x 500 ft rolls — shown in imperial, US market. The link sets both, so the result they see is the one on your screen.
Show calculation logicHide calculation logic
How this was calculated
Formula source(s)
- Total wire needed = boundary perimeter + twisted (non-signal) wire from the transmitter to the boundary, doubled for the wire pair, plus 10% for burial slack and splices; boundary wire is commonly stocked in 500 ft rolls in North America, while metric-market spool lengths vary by supplier, so on metric the answer is given as the length of wire required rather than a spool count
Inputs used
- Boundary Loop Length
- 490 ft
- Distance From Transmitter to Boundary
- 49 ft
Intermediate steps
- Total wire needed (with waste)
- 646.8 linear ft
What this calculation does not cover
- Counts wire, not layout. Two runs of boundary wire that come back within about 10 ft (3 m) of each other cancel each other's fields and leave a stretch of boundary carrying no correction signal at all — the dog finds it long before you do. Keeping parallel runs apart, or twisting the return leg so it stops radiating, is what the routing has to satisfy, and it normally adds wire beyond the measured boundary.
- Buried metal changes the signal the wire exists to produce. Running the loop alongside a chain-link fence, over rebar-reinforced concrete or on top of a buried utility line distorts or swallows the field, so the wire has to be offset from those runs — more length than the property line suggests, and without the offset there is no warning at the one fence line you most wanted covered.
- Assumes one unbroken conductor. Every joint is a failure point, and a joint twisted and taped rather than made up in a gel-filled splice capsule corrodes within a season and opens the loop. The whole system then goes dead with no indication at the collar, and finding the break takes an RF wire locator rather than a shovel.
Estimated cost — your price
This site holds no price list for this material — local prices vary too much to publish honestly. Enter your supplier's price and the result is costed with it.
Computed in your browser — nothing you enter is uploaded. Presented in US customary units and US trade terminology. Where a formula follows a published standard, that standard and its edition are cited beside it on this page; where none governs, the page says so. Local amendments override model codes — verify against the code in force where you build.
Sources checked 2026-09-06 · in the site-wide review of 2026-09-06 · v1.0.1
Regulatory standards & verification citations1
- Total wire needed = boundary perimeter + twisted (non-signal) wire from the transmitter to the boundary, doubled for the wire pair, plus 10% for burial slack and splices; boundary wire is commonly stocked in 500 ft rolls in North America, while metric-market spool lengths vary by supplier, so on metric the answer is given as the length of wire required rather than a spool count
Cite this page
Your workspace
Most jobs need more than one number. Add the calculators you need next and they open right here, underneath this one — your figures stay on screen and nothing is lost to a page change.